5x^2+18x-74160=0

Solution for 5x^2+18x-74160=0 equation:

5x^2+18x-74160=0

a = 5; b = 18; c = -74160;
Δ = b2-4ac
Δ = 182-4·5·(-74160)
Δ = 1483524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1483524}=1218$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-1218}{2*5}=\frac{-1236}{10}
=-123+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+1218}{2*5}=\frac{1200}{10}
=120
$